3(2x+1/3)= 4(3x-1/2)
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[tex]3(2x + \frac{1}{3} ) = 4(3x - \frac{1}{2} ) \\ 3(2x) + 3( \frac{1}{3} ) = 4(3x) + 4( - \frac{1}{2} ) \\ 6x + 1 = 12x - 2 \\ 1 = 12x - 6x - 2 \\ 1 = 6x - 2 \\ 1 + 2 = 6x \\ [/tex]
[tex]3 = 6x \\ \frac{3}{6} = x \\ \frac{1}{2} = x[/tex]
Jadi nilai x adalah 1/2
Jawaban:
[tex]\sf{x}{=}{-}{\frac {1}{6}}[/tex]
Penjelasan dengan langkah-langkah:
3([tex]\sf{2x}{+}{\frac {1}{3}}[/tex]) = 4([tex]\sf{3x}{-}{\frac {1}{2}}[/tex])
= 6x + 1 = 12x + 2
= 6x - 12x = 2 - 1
= -6x = 1
= [tex]\sf{\red{x{={-{\frac {1}{6}}}}}}[/tex]
