S.Q
Jika:
U = 12
X = U - 3!
Y = X²
Tentukan:
U × Y + X
[D-8, 1/5]
Jika:
U = 12
X = U - 3!
Y = X²
Tentukan:
U × Y + X
[D-8, 1/5]
DIKETAHUI
U = 12
X = U - 3!
X = 12 - ( 3 × 2 × 1 )
X = 12 - ( 6 × 1 )
X = 12 - 6
X = 6
Y = X²
Y = 6²
Y = ( 6 × 6 )
Y = 36
DITANYA
U × Y + X
= 12 × 36 + 6
= 432 + 6
= 438
⃢~ Opung~⃠⃫⃟⃤᳗᳐
Nilai U
- 12
Nilai X
- U - 3!
- 12 - 3!
- 12 - ( 3 × 2 × 1 )
- 12 - 6
- 6
Nilai Y
- x²
- ( u - 3! ) × ( u - 3! )
- ( 12 - 3! ) × ( 12 - 3! )
- ( 12 - ( 3 × 2 × 1 ) ) × ( 12 - ( 3 × 2 × 1 ) )
- ( 12 - 6 ) × ( 12 - 6 )
- 6 × 6
- 36
Maka :
- Nilai U × Nilai Y + Nilai X
- 12 × 36 + 6
- 432 + 6
- 438
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